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153330116143 = 349439341307
BaseRepresentation
bin1000111011001100101…
…1111110011000101111
3112122202211122221102111
42032303023332120233
510003010002204033
6154234444304451
714035443324451
oct2166313763057
9478684587374
10153330116143
115a032942756
1225871b42127
13115c7477599
1475c7b6a2d1
153ec61307cd
hex23b32fe62f

153330116143 has 4 divisors (see below), whose sum is σ = 153769457800. Its totient is φ = 152890774488.

The previous prime is 153330116131. The next prime is 153330116161. The reversal of 153330116143 is 341611033351.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 153330116143 - 25 = 153330116111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (153330116543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219670305 + ... + 219671002.

It is an arithmetic number, because the mean of its divisors is an integer number (38442364450).

Almost surely, 2153330116143 is an apocalyptic number.

153330116143 is a deficient number, since it is larger than the sum of its proper divisors (439341657).

153330116143 is an equidigital number, since it uses as much as digits as its factorization.

153330116143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 439341656.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 153330116143 its reverse (341611033351), we get a palindrome (494941149494).

The spelling of 153330116143 in words is "one hundred fifty-three billion, three hundred thirty million, one hundred sixteen thousand, one hundred forty-three".

Divisors: 1 349 439341307 153330116143