Base | Representation |
---|---|
bin | 1000111011010001100… |
… | …1011100101011110111 |
3 | 112122211020212202101210 |
4 | 2032310121130223313 |
5 | 10003030202102320 |
6 | 154240451452503 |
7 | 14036111052102 |
oct | 2166431345367 |
9 | 478736782353 |
10 | 153350425335 |
11 | 5a043354308 |
12 | 258788b7133 |
13 | 115cb738663 |
14 | 75ca735739 |
15 | 3ec7ce30e0 |
hex | 23b465caf7 |
153350425335 has 32 divisors (see below), whose sum is σ = 261112496832. Its totient is φ = 76585134080.
The previous prime is 153350425313. The next prime is 153350425391. The reversal of 153350425335 is 533524053351.
It is not a de Polignac number, because 153350425335 - 221 = 153348328183 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153350425293 and 153350425302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1476096 + ... + 1576565.
It is an arithmetic number, because the mean of its divisors is an integer number (8159765526).
Almost surely, 2153350425335 is an apocalyptic number.
153350425335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
153350425335 is a deficient number, since it is larger than the sum of its proper divisors (107762071497).
153350425335 is a wasteful number, since it uses less digits than its factorization.
153350425335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3052883.
The product of its (nonzero) digits is 405000, while the sum is 39.
Adding to 153350425335 its reverse (533524053351), we get a palindrome (686874478686).
The spelling of 153350425335 in words is "one hundred fifty-three billion, three hundred fifty million, four hundred twenty-five thousand, three hundred thirty-five".
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