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15340250113 = 29663517151
BaseRepresentation
bin11100100100101100…
…11010010000000001
31110121002101110002121
432102112122100001
5222404101000423
611014110444241
71052100655156
oct162226322001
943532343077
1015340250113
116562197a61
122b81503681
1315a619a496
14a574b422d
155ebb2445d
hex39259a401

15340250113 has 4 divisors (see below), whose sum is σ = 15340796928. Its totient is φ = 15339703300.

The previous prime is 15340250111. The next prime is 15340250137. The reversal of 15340250113 is 31105204351.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15340250113 - 21 = 15340250111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15340250111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 228913 + ... + 288238.

It is an arithmetic number, because the mean of its divisors is an integer number (3835199232).

Almost surely, 215340250113 is an apocalyptic number.

It is an amenable number.

15340250113 is a deficient number, since it is larger than the sum of its proper divisors (546815).

15340250113 is an equidigital number, since it uses as much as digits as its factorization.

15340250113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 546814.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 15340250113 its reverse (31105204351), we get a palindrome (46445454464).

The spelling of 15340250113 in words is "fifteen billion, three hundred forty million, two hundred fifty thousand, one hundred thirteen".

Divisors: 1 29663 517151 15340250113