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153411402111113 is a prime number
BaseRepresentation
bin100010111000011011100000…
…001000001001100010001001
3202010011222122101101200212002
4202320123200020021202021
5130101443022420023423
61302140120350400345
744212415362231106
oct4270334010114211
9663158571350762
10153411402111113
1144977457079163
12152581a82000b5
13677a830031c53
1429c5219939aad
1512b08b158a228
hex8b86e0209889

153411402111113 has 2 divisors, whose sum is σ = 153411402111114. Its totient is φ = 153411402111112.

The previous prime is 153411402111109. The next prime is 153411402111133. The reversal of 153411402111113 is 311111204114351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132894968448064 + 20516433663049 = 11528008^2 + 4529507^2 .

It is a cyclic number.

It is not a de Polignac number, because 153411402111113 - 22 = 153411402111109 is a prime.

It is not a weakly prime, because it can be changed into another prime (153411402111133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76705701055556 + 76705701055557.

It is an arithmetic number, because the mean of its divisors is an integer number (76705701055557).

Almost surely, 2153411402111113 is an apocalyptic number.

It is an amenable number.

153411402111113 is a deficient number, since it is larger than the sum of its proper divisors (1).

153411402111113 is an equidigital number, since it uses as much as digits as its factorization.

153411402111113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 29.

Adding to 153411402111113 its reverse (311111204114351), we get a palindrome (464522606225464).

The spelling of 153411402111113 in words is "one hundred fifty-three trillion, four hundred eleven billion, four hundred two million, one hundred eleven thousand, one hundred thirteen".