153411402111133 has 2 divisors, whose sum is σ = 153411402111134. Its totient is φ = 153411402111132.

The previous prime is 153411402111113. The next prime is 153411402111157. The reversal of 153411402111133 is 331111204114351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143163067615929 + 10248334495204 = 11965077^2 + 3201302^2 .

It is a cyclic number.

It is not a de Polignac number, because 153411402111133 - 2⁴¹ = 151212378855581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 153411402111095 and 153411402111104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (153411402111113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76705701055566 + 76705701055567.

It is an arithmetic number, because the mean of its divisors is an integer number (76705701055567).

Almost surely, 2^{153411402111133} is an apocalyptic number.

It is an amenable number.

153411402111133 is a deficient number, since it is larger than the sum of its proper divisors (1).

153411402111133 is an equidigital number, since it uses as much as digits as its factorization.

153411402111133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 31.

Adding to 153411402111133 its reverse (331111204114351), we get a palindrome (484522606225484).

The spelling of 153411402111133 in words is "one hundred fifty-three trillion, four hundred eleven billion, four hundred two million, one hundred eleven thousand, one hundred thirty-three".