153411402111131 has 4 divisors (see below), whose sum is σ = 153411877278912. Its totient is φ = 153410926943352.

The previous prime is 153411402111113. The next prime is 153411402111133. The reversal of 153411402111131 is 131111204114351.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 153411402111131 - 2¹⁸ = 153411401848987 is a prime.

It is a super-2 number, since 2×153411402111131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 153411402111094 and 153411402111103.

It is not an unprimeable number, because it can be changed into a prime (153411402111133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 237099275 + ... + 237745428.

It is an arithmetic number, because the mean of its divisors is an integer number (38352969319728).

Almost surely, 2^{153411402111131} is an apocalyptic number.

153411402111131 is a deficient number, since it is larger than the sum of its proper divisors (475167781).

153411402111131 is an equidigital number, since it uses as much as digits as its factorization.

153411402111131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 475167780.

The product of its (nonzero) digits is 1440, while the sum is 29.

Adding to 153411402111131 its reverse (131111204114351), we get a palindrome (284522606225482).

The spelling of 153411402111131 in words is "one hundred fifty-three trillion, four hundred eleven billion, four hundred two million, one hundred eleven thousand, one hundred thirty-one".