Base | Representation |
---|---|
bin | 10110010100110001000… |
… | …111100101000010000101 |
3 | 12102122211222100102120021 |
4 | 112110301013211002011 |
5 | 200113343103114244 |
6 | 3132433550135141 |
7 | 215560051461562 |
oct | 26246107450205 |
9 | 5378758312507 |
10 | 1534127394949 |
11 | 54168aa13326 |
12 | 2093a81b14b1 |
13 | b188a915c26 |
14 | 54375d0b869 |
15 | 29d8d510284 |
hex | 165311e5085 |
1534127394949 has 2 divisors, whose sum is σ = 1534127394950. Its totient is φ = 1534127394948.
The previous prime is 1534127394931. The next prime is 1534127394977. The reversal of 1534127394949 is 9494937214351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1024309974724 + 509817420225 = 1012082^2 + 714015^2 .
It is a cyclic number.
It is not a de Polignac number, because 1534127394949 - 223 = 1534119006341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1534127391949) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 767063697474 + 767063697475.
It is an arithmetic number, because the mean of its divisors is an integer number (767063697475).
Almost surely, 21534127394949 is an apocalyptic number.
It is an amenable number.
1534127394949 is a deficient number, since it is larger than the sum of its proper divisors (1).
1534127394949 is an equidigital number, since it uses as much as digits as its factorization.
1534127394949 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 29393280, while the sum is 61.
The spelling of 1534127394949 in words is "one trillion, five hundred thirty-four billion, one hundred twenty-seven million, three hundred ninety-four thousand, nine hundred forty-nine".
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