Base | Representation |
---|---|
bin | 10110010101100111000… |
… | …110111101000110011111 |
3 | 12102202012002210010221120 |
4 | 112111213012331012133 |
5 | 200122221444413210 |
6 | 3133103504502023 |
7 | 215621360631654 |
oct | 26254706750637 |
9 | 5382162703846 |
10 | 1535033201055 |
11 | 542005250912 |
12 | 2095bb61a913 |
13 | b19a3493283 |
14 | 54420339c2b |
15 | 29de2cd7270 |
hex | 165671bd19f |
1535033201055 has 16 divisors (see below), whose sum is σ = 2462465802240. Its totient is φ = 816546813728.
The previous prime is 1535033201041. The next prime is 1535033201131. The reversal of 1535033201055 is 5501023305351.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1535033201055 - 29 = 1535033200543 is a prime.
It is a super-2 number, since 2×15350332010552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 133591575 + ... + 133603064.
It is an arithmetic number, because the mean of its divisors is an integer number (153904112640).
Almost surely, 21535033201055 is an apocalyptic number.
1535033201055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1535033201055 is a deficient number, since it is larger than the sum of its proper divisors (927432601185).
1535033201055 is a wasteful number, since it uses less digits than its factorization.
1535033201055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 267195030.
The product of its (nonzero) digits is 33750, while the sum is 33.
The spelling of 1535033201055 in words is "one trillion, five hundred thirty-five billion, thirty-three million, two hundred one thousand, fifty-five".
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