153515211300113 has 4 divisors (see below), whose sum is σ = 165324073707828. Its totient is φ = 141706348892400.

The previous prime is 153515211300019. The next prime is 153515211300149. The reversal of 153515211300113 is 311003112515351.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 64219836457984 + 89295374842129 = 8013728^2 + 9449623^2 .

It is a cyclic number.

It is not a de Polignac number, because 153515211300113 - 2²⁶ = 153515144191249 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 153515211300113.

It is not an unprimeable number, because it can be changed into a prime (153515211300313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5904431203838 + ... + 5904431203863.

It is an arithmetic number, because the mean of its divisors is an integer number (41331018426957).

Almost surely, 2^{153515211300113} is an apocalyptic number.

153515211300113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

153515211300113 is a deficient number, since it is larger than the sum of its proper divisors (11808862407715).

153515211300113 is a wasteful number, since it uses less digits than its factorization.

153515211300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11808862407714.

The product of its (nonzero) digits is 6750, while the sum is 32.

Adding to 153515211300113 its reverse (311003112515351), we get a palindrome (464518323815464).

The spelling of 153515211300113 in words is "one hundred fifty-three trillion, five hundred fifteen billion, two hundred eleven million, three hundred thousand, one hundred thirteen".