1536091241 has 2 divisors, whose sum is σ = 1536091242. Its totient is φ = 1536091240.

The previous prime is 1536091237. The next prime is 1536091243. The reversal of 1536091241 is 1421906351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 992502016 + 543589225 = 31504^2 + 23315^2 .

It is a cyclic number.

It is not a de Polignac number, because 1536091241 - 2² = 1536091237 is a prime.

It is a super-3 number, since 3×1536091241³ (a number of 29 digits) contains 333 as substring.

Together with 1536091243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1536091198 and 1536091207.

It is not a weakly prime, because it can be changed into another prime (1536091243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 768045620 + 768045621.

It is an arithmetic number, because the mean of its divisors is an integer number (768045621).

Almost surely, 2^1536091241 is an apocalyptic number.

It is an amenable number.

1536091241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1536091241 is an equidigital number, since it uses as much as digits as its factorization.

1536091241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 32.

The square root of 1536091241 is about 39192.9998979410. Note that the first 3 decimals coincide. The cubic root of 1536091241 is about 1153.8225016778.

Adding to 1536091241 its reverse (1421906351), we get a palindrome (2957997592).

It can be divided in two parts, 15360 and 91241, that added together give a palindrome (106601).

The spelling of 1536091241 in words is "one billion, five hundred thirty-six million, ninety-one thousand, two hundred forty-one".