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1540094117 is a prime number
BaseRepresentation
bin101101111001011…
…1111100010100101
310222022221212221212
41123302333202211
511123231002432
6412453321205
753110404212
oct13362774245
93868855855
101540094117
11720385561
1236b936205
131b70bc8c3
1410877cb09
15903192b2
hex5bcbf8a5

1540094117 has 2 divisors, whose sum is σ = 1540094118. Its totient is φ = 1540094116.

The previous prime is 1540094089. The next prime is 1540094147. The reversal of 1540094117 is 7114900451.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 815730721 + 724363396 = 28561^2 + 26914^2 .

It is an emirp because it is prime and its reverse (7114900451) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1540094117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1540094147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770047058 + 770047059.

It is an arithmetic number, because the mean of its divisors is an integer number (770047059).

Almost surely, 21540094117 is an apocalyptic number.

It is an amenable number.

1540094117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1540094117 is an equidigital number, since it uses as much as digits as its factorization.

1540094117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 32.

The square root of 1540094117 is about 39244.0328839940. The cubic root of 1540094117 is about 1154.8238749951.

Adding to 1540094117 its reverse (7114900451), we get a palindrome (8654994568).

The spelling of 1540094117 in words is "one billion, five hundred forty million, ninety-four thousand, one hundred seventeen".