Base | Representation |
---|---|
bin | 1110000000011101111110… |
… | …1011010011110000000111 |
3 | 2000112100012211112212212201 |
4 | 3200013133223103300013 |
5 | 4004313134332202143 |
6 | 52431115101255331 |
7 | 3146462231441341 |
oct | 340073753236007 |
9 | 60470184485781 |
10 | 15401210428423 |
11 | 49a8686861746 |
12 | 1888a36264547 |
13 | 879435563b51 |
14 | 3b35cb720291 |
15 | 1ba94a45864d |
hex | e01dfad3c07 |
15401210428423 has 2 divisors, whose sum is σ = 15401210428424. Its totient is φ = 15401210428422.
The previous prime is 15401210428411. The next prime is 15401210428447. The reversal of 15401210428423 is 32482401210451.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15401210428423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15401210428403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7700605214211 + 7700605214212.
It is an arithmetic number, because the mean of its divisors is an integer number (7700605214212).
Almost surely, 215401210428423 is an apocalyptic number.
15401210428423 is a deficient number, since it is larger than the sum of its proper divisors (1).
15401210428423 is an equidigital number, since it uses as much as digits as its factorization.
15401210428423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 61440, while the sum is 37.
Adding to 15401210428423 its reverse (32482401210451), we get a palindrome (47883611638874).
The spelling of 15401210428423 in words is "fifteen trillion, four hundred one billion, two hundred ten million, four hundred twenty-eight thousand, four hundred twenty-three".
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