154013201 has 4 divisors (see below), whose sum is σ = 154076400. Its totient is φ = 153950004.

The previous prime is 154013191. The next prime is 154013207. The reversal of 154013201 is 102310451.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 102310451 = 79 ⋅1295069.

It is a cyclic number.

It is not a de Polignac number, because 154013201 - 2¹⁸ = 153751057 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 154013201.

It is not an unprimeable number, because it can be changed into a prime (154013207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27791 + ... + 32868.

It is an arithmetic number, because the mean of its divisors is an integer number (38519100).

Almost surely, 2^154013201 is an apocalyptic number.

It is an amenable number.

154013201 is a deficient number, since it is larger than the sum of its proper divisors (63199).

154013201 is an equidigital number, since it uses as much as digits as its factorization.

154013201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63198.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 154013201 is about 12410.2055180404. The cubic root of 154013201 is about 536.0261564146.

Adding to 154013201 its reverse (102310451), we get a palindrome (256323652).

It can be divided in two parts, 1540 and 13201, that added together give a palindrome (14741).

The spelling of 154013201 in words is "one hundred fifty-four million, thirteen thousand, two hundred one".