Base | Representation |
---|---|
bin | 10110011010101010000… |
… | …011011101000011100111 |
3 | 12110021011200221022112202 |
4 | 112122222003131003213 |
5 | 200214321014333020 |
6 | 3135401254005115 |
7 | 216202551132113 |
oct | 26325203350347 |
9 | 5407150838482 |
10 | 1540451324135 |
11 | 544335681989 |
12 | 20a67204679b |
13 | b2357b3a469 |
14 | 547b5b5c743 |
15 | 2a10d7d1e75 |
hex | 166aa0dd0e7 |
1540451324135 has 4 divisors (see below), whose sum is σ = 1848541588968. Its totient is φ = 1232361059304.
The previous prime is 1540451324131. The next prime is 1540451324147. The reversal of 1540451324135 is 5314231540451.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1540451324135 - 22 = 1540451324131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1540451324131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154045132409 + ... + 154045132418.
It is an arithmetic number, because the mean of its divisors is an integer number (462135397242).
Almost surely, 21540451324135 is an apocalyptic number.
1540451324135 is a deficient number, since it is larger than the sum of its proper divisors (308090264833).
1540451324135 is an equidigital number, since it uses as much as digits as its factorization.
1540451324135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 308090264832.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 1540451324135 its reverse (5314231540451), we get a palindrome (6854682864586).
The spelling of 1540451324135 in words is "one trillion, five hundred forty billion, four hundred fifty-one million, three hundred twenty-four thousand, one hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •