Base | Representation |
---|---|
bin | 10110011011001101111… |
… | …011001011011000000111 |
3 | 12110022201122100102221201 |
4 | 112123031323023120013 |
5 | 200222034100244333 |
6 | 3135541112523331 |
7 | 216223506340612 |
oct | 26331573133007 |
9 | 5408648312851 |
10 | 1541053134343 |
11 | 544614356898 |
12 | 20a7bb6b0547 |
13 | b242271ac88 |
14 | 54831a57179 |
15 | 2a14655b17d |
hex | 166cdecb607 |
1541053134343 has 2 divisors, whose sum is σ = 1541053134344. Its totient is φ = 1541053134342.
The previous prime is 1541053134277. The next prime is 1541053134377. The reversal of 1541053134343 is 3434313501451.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1541053134343 is a prime.
It is a super-3 number, since 3×15410531343433 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1541053114343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770526567171 + 770526567172.
It is an arithmetic number, because the mean of its divisors is an integer number (770526567172).
Almost surely, 21541053134343 is an apocalyptic number.
1541053134343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1541053134343 is an equidigital number, since it uses as much as digits as its factorization.
1541053134343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 37.
Adding to 1541053134343 its reverse (3434313501451), we get a palindrome (4975366635794).
The spelling of 1541053134343 in words is "one trillion, five hundred forty-one billion, fifty-three million, one hundred thirty-four thousand, three hundred forty-three".
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