Base | Representation |
---|---|
bin | 11100101110010000… |
… | …01101000001101101 |
3 | 1110210200020002112212 |
4 | 32113020031001231 |
5 | 223040111141023 |
6 | 11030052540205 |
7 | 1054063224266 |
oct | 162710150155 |
9 | 43720202485 |
10 | 15420412013 |
11 | 65a3469866 |
12 | 2ba4321665 |
13 | 15b9986466 |
14 | a63dbd96d |
15 | 603baae78 |
hex | 39720d06d |
15420412013 has 2 divisors, whose sum is σ = 15420412014. Its totient is φ = 15420412012.
The previous prime is 15420411977. The next prime is 15420412043. The reversal of 15420412013 is 31021402451.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10129013449 + 5291398564 = 100643^2 + 72742^2 .
It is a cyclic number.
It is not a de Polignac number, because 15420412013 - 28 = 15420411757 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 15420412013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15420412043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7710206006 + 7710206007.
It is an arithmetic number, because the mean of its divisors is an integer number (7710206007).
Almost surely, 215420412013 is an apocalyptic number.
It is an amenable number.
15420412013 is a deficient number, since it is larger than the sum of its proper divisors (1).
15420412013 is an equidigital number, since it uses as much as digits as its factorization.
15420412013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 15420412013 its reverse (31021402451), we get a palindrome (46441814464).
The spelling of 15420412013 in words is "fifteen billion, four hundred twenty million, four hundred twelve thousand, thirteen".
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