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15420412013 is a prime number
BaseRepresentation
bin11100101110010000…
…01101000001101101
31110210200020002112212
432113020031001231
5223040111141023
611030052540205
71054063224266
oct162710150155
943720202485
1015420412013
1165a3469866
122ba4321665
1315b9986466
14a63dbd96d
15603baae78
hex39720d06d

15420412013 has 2 divisors, whose sum is σ = 15420412014. Its totient is φ = 15420412012.

The previous prime is 15420411977. The next prime is 15420412043. The reversal of 15420412013 is 31021402451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10129013449 + 5291398564 = 100643^2 + 72742^2 .

It is a cyclic number.

It is not a de Polignac number, because 15420412013 - 28 = 15420411757 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 15420412013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15420412043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7710206006 + 7710206007.

It is an arithmetic number, because the mean of its divisors is an integer number (7710206007).

Almost surely, 215420412013 is an apocalyptic number.

It is an amenable number.

15420412013 is a deficient number, since it is larger than the sum of its proper divisors (1).

15420412013 is an equidigital number, since it uses as much as digits as its factorization.

15420412013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 15420412013 its reverse (31021402451), we get a palindrome (46441814464).

The spelling of 15420412013 in words is "fifteen billion, four hundred twenty million, four hundred twelve thousand, thirteen".