Base | Representation |
---|---|
bin | 1110000001110000010111… |
… | …0100010000010000100111 |
3 | 2000121110022001021211200102 |
4 | 3200130011310100100213 |
5 | 4010143432214102403 |
6 | 52445213332334315 |
7 | 3151204242432152 |
oct | 340340564202047 |
9 | 60543261254612 |
10 | 15423325144103 |
11 | 4a06aa4a5a978 |
12 | 189118847439b |
13 | 87b54b0ac726 |
14 | 3b46c8802c99 |
15 | 1bb2e1b96b88 |
hex | e0705d10427 |
15423325144103 has 2 divisors, whose sum is σ = 15423325144104. Its totient is φ = 15423325144102.
The previous prime is 15423325144079. The next prime is 15423325144109. The reversal of 15423325144103 is 30144152332451.
It is a strong prime.
It is an emirp because it is prime and its reverse (30144152332451) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15423325144103 - 218 = 15423324881959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15423325144109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7711662572051 + 7711662572052.
It is an arithmetic number, because the mean of its divisors is an integer number (7711662572052).
Almost surely, 215423325144103 is an apocalyptic number.
15423325144103 is a deficient number, since it is larger than the sum of its proper divisors (1).
15423325144103 is an equidigital number, since it uses as much as digits as its factorization.
15423325144103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 15423325144103 its reverse (30144152332451), we get a palindrome (45567477476554).
The spelling of 15423325144103 in words is "fifteen trillion, four hundred twenty-three billion, three hundred twenty-five million, one hundred forty-four thousand, one hundred three".
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