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154269053441 is a prime number
BaseRepresentation
bin1000111110101100100…
…1101111001000000001
3112202012021102220020222
42033223021233020001
510011420334202231
6154511545112425
714100634214126
oct2175311571001
9482167386228
10154269053441
115a47494a198
1225a94488715
1311716b54b99
14767674074d
15402d79e27b
hex23eb26f201

154269053441 has 2 divisors, whose sum is σ = 154269053442. Its totient is φ = 154269053440.

The previous prime is 154269053431. The next prime is 154269053443. The reversal of 154269053441 is 144350962451.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112691804416 + 41577249025 = 335696^2 + 203905^2 .

It is a cyclic number.

It is not a de Polignac number, because 154269053441 - 210 = 154269052417 is a prime.

It is a super-2 number, since 2×1542690534412 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 154269053443, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 154269053392 and 154269053401.

It is not a weakly prime, because it can be changed into another prime (154269053443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77134526720 + 77134526721.

It is an arithmetic number, because the mean of its divisors is an integer number (77134526721).

Almost surely, 2154269053441 is an apocalyptic number.

It is an amenable number.

154269053441 is a deficient number, since it is larger than the sum of its proper divisors (1).

154269053441 is an equidigital number, since it uses as much as digits as its factorization.

154269053441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 44.

The spelling of 154269053441 in words is "one hundred fifty-four billion, two hundred sixty-nine million, fifty-three thousand, four hundred forty-one".