Base | Representation |
---|---|
bin | 11100101111101001… |
… | …11010101000010101 |
3 | 1110211111021120220201 |
4 | 32113310322220111 |
5 | 223101111230031 |
6 | 11031152100501 |
7 | 1054264652545 |
oct | 162764725025 |
9 | 43744246821 |
10 | 15432133141 |
11 | 65aa045047 |
12 | 2ba8234731 |
13 | 15bc22b539 |
14 | a65791325 |
15 | 604c23d61 |
hex | 397d3aa15 |
15432133141 has 2 divisors, whose sum is σ = 15432133142. Its totient is φ = 15432133140.
The previous prime is 15432133139. The next prime is 15432133147. The reversal of 15432133141 is 14133123451.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14759820100 + 672313041 = 121490^2 + 25929^2 .
It is a cyclic number.
It is not a de Polignac number, because 15432133141 - 21 = 15432133139 is a prime.
Together with 15432133139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15432133147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7716066570 + 7716066571.
It is an arithmetic number, because the mean of its divisors is an integer number (7716066571).
Almost surely, 215432133141 is an apocalyptic number.
It is an amenable number.
15432133141 is a deficient number, since it is larger than the sum of its proper divisors (1).
15432133141 is an equidigital number, since it uses as much as digits as its factorization.
15432133141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4320, while the sum is 28.
Adding to 15432133141 its reverse (14133123451), we get a palindrome (29565256592).
The spelling of 15432133141 in words is "fifteen billion, four hundred thirty-two million, one hundred thirty-three thousand, one hundred forty-one".
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