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154391039993 is a prime number
BaseRepresentation
bin1000111111001001101…
…1000100111111111001
3112202111202222110100102
42033302123010333321
510012143101234433
6154532023445145
714103645121061
oct2176233047771
9482452873312
10154391039993
115a527798523
1225b092b67b5
13117361c6088
147688a163a1
1540393484e8
hex23f26c4ff9

154391039993 has 2 divisors, whose sum is σ = 154391039994. Its totient is φ = 154391039992.

The previous prime is 154391039989. The next prime is 154391040049. The reversal of 154391039993 is 399930193451.

It is an a-pointer prime, because the next prime (154391040049) can be obtained adding 154391039993 to its sum of digits (56).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 151140557824 + 3250482169 = 388768^2 + 57013^2 .

It is a cyclic number.

It is not a de Polignac number, because 154391039993 - 22 = 154391039989 is a prime.

It is not a weakly prime, because it can be changed into another prime (154391039963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77195519996 + 77195519997.

It is an arithmetic number, because the mean of its divisors is an integer number (77195519997).

Almost surely, 2154391039993 is an apocalyptic number.

It is an amenable number.

154391039993 is a deficient number, since it is larger than the sum of its proper divisors (1).

154391039993 is an equidigital number, since it uses as much as digits as its factorization.

154391039993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3542940, while the sum is 56.

The spelling of 154391039993 in words is "one hundred fifty-four billion, three hundred ninety-one million, thirty-nine thousand, nine hundred ninety-three".