Base | Representation |
---|---|
bin | 11100110110101010… |
… | …11101011110101011 |
3 | 1110222121001010202202 |
4 | 32123111131132223 |
5 | 223211143334024 |
6 | 11041053450415 |
7 | 1055611203023 |
oct | 163325353653 |
9 | 43877033682 |
10 | 15490996139 |
11 | 662a299753 |
12 | 3003aa0a0b |
13 | 15cb49ab08 |
14 | a6d514a83 |
15 | 609e9ebae |
hex | 39b55d7ab |
15490996139 has 4 divisors (see below), whose sum is σ = 16402231224. Its totient is φ = 14579761056.
The previous prime is 15490996123. The next prime is 15490996141. The reversal of 15490996139 is 93169909451.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 93169909451 = 101 ⋅922474351.
It is a cyclic number.
It is not a de Polignac number, because 15490996139 - 24 = 15490996123 is a prime.
It is a super-2 number, since 2×154909961392 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15490996189) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455617517 + ... + 455617550.
It is an arithmetic number, because the mean of its divisors is an integer number (4100557806).
Almost surely, 215490996139 is an apocalyptic number.
15490996139 is a deficient number, since it is larger than the sum of its proper divisors (911235085).
15490996139 is an equidigital number, since it uses as much as digits as its factorization.
15490996139 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 911235084.
The product of its (nonzero) digits is 2361960, while the sum is 56.
The spelling of 15490996139 in words is "fifteen billion, four hundred ninety million, nine hundred ninety-six thousand, one hundred thirty-nine".
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