Base | Representation |
---|---|
bin | 1001000001100010000… |
… | …0101000101110001101 |
3 | 112211011022100120120002 |
4 | 2100120200220232031 |
5 | 10020000141444440 |
6 | 155115251334045 |
7 | 14125534344245 |
oct | 2203040505615 |
9 | 484138316502 |
10 | 155030031245 |
11 | 5a825458071 |
12 | 260672b1325 |
13 | 118086c42cb |
14 | 770982cb25 |
15 | 40754b9115 |
hex | 2418828b8d |
155030031245 has 4 divisors (see below), whose sum is σ = 186036037500. Its totient is φ = 124024024992.
The previous prime is 155030031223. The next prime is 155030031259. The reversal of 155030031245 is 542130030551.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 97096429609 + 57933601636 = 311603^2 + 240694^2 .
It is a cyclic number.
It is not a de Polignac number, because 155030031245 - 216 = 155029965709 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15503003120 + ... + 15503003129.
It is an arithmetic number, because the mean of its divisors is an integer number (46509009375).
Almost surely, 2155030031245 is an apocalyptic number.
It is an amenable number.
155030031245 is a deficient number, since it is larger than the sum of its proper divisors (31006006255).
155030031245 is an equidigital number, since it uses as much as digits as its factorization.
155030031245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31006006254.
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 155030031245 its reverse (542130030551), we get a palindrome (697160061796).
The spelling of 155030031245 in words is "one hundred fifty-five billion, thirty million, thirty-one thousand, two hundred forty-five".
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