Base | Representation |
---|---|
bin | 1001000001100010000… |
… | …1101110101001001111 |
3 | 112211011022220010102120 |
4 | 2100120201232221033 |
5 | 10020000230131042 |
6 | 155115301424023 |
7 | 14125536646242 |
oct | 2203041565117 |
9 | 484138803376 |
10 | 155030317647 |
11 | 5a825633267 |
12 | 2606740b013 |
13 | 1180879478a |
14 | 77098a5259 |
15 | 4075523dec |
hex | 241886ea4f |
155030317647 has 4 divisors (see below), whose sum is σ = 206707090200. Its totient is φ = 103353545096.
The previous prime is 155030317643. The next prime is 155030317693. The reversal of 155030317647 is 746713030551.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 155030317647 - 22 = 155030317643 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 155030317599 and 155030317608.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (155030317643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25838386272 + ... + 25838386277.
It is an arithmetic number, because the mean of its divisors is an integer number (51676772550).
Almost surely, 2155030317647 is an apocalyptic number.
155030317647 is a deficient number, since it is larger than the sum of its proper divisors (51676772553).
155030317647 is an equidigital number, since it uses as much as digits as its factorization.
155030317647 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51676772552.
The product of its (nonzero) digits is 264600, while the sum is 42.
The spelling of 155030317647 in words is "one hundred fifty-five billion, thirty million, three hundred seventeen thousand, six hundred forty-seven".
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