Base | Representation |
---|---|
bin | 10110100011111101000… |
… | …001000010111000000111 |
3 | 12111012221100110220102111 |
4 | 112203331001002320013 |
5 | 200400241340324020 |
6 | 3144131550521451 |
7 | 220005115132612 |
oct | 26437501027007 |
9 | 5435840426374 |
10 | 1550433136135 |
11 | 5485980a3a94 |
12 | 210598b06287 |
13 | b3288b2a1b0 |
14 | 55081709179 |
15 | 2a4e4c9ad5a |
hex | 168fd042e07 |
1550433136135 has 16 divisors (see below), whose sum is σ = 2003762769120. Its totient is φ = 1144863181440.
The previous prime is 1550433136127. The next prime is 1550433136141. The reversal of 1550433136135 is 5316313340551.
It is not a de Polignac number, because 1550433136135 - 23 = 1550433136127 is a prime.
It is a super-2 number, since 2×15504331361352 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 301396 + ... + 1786534.
It is an arithmetic number, because the mean of its divisors is an integer number (125235173070).
Almost surely, 21550433136135 is an apocalyptic number.
1550433136135 is a deficient number, since it is larger than the sum of its proper divisors (453329632985).
1550433136135 is a wasteful number, since it uses less digits than its factorization.
1550433136135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1501218.
The product of its (nonzero) digits is 243000, while the sum is 40.
Adding to 1550433136135 its reverse (5316313340551), we get a palindrome (6866746476686).
The spelling of 1550433136135 in words is "one trillion, five hundred fifty billion, four hundred thirty-three million, one hundred thirty-six thousand, one hundred thirty-five".
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