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1550433136135 = 513160611485139
BaseRepresentation
bin10110100011111101000…
…001000010111000000111
312111012221100110220102111
4112203331001002320013
5200400241340324020
63144131550521451
7220005115132612
oct26437501027007
95435840426374
101550433136135
115485980a3a94
12210598b06287
13b3288b2a1b0
1455081709179
152a4e4c9ad5a
hex168fd042e07

1550433136135 has 16 divisors (see below), whose sum is σ = 2003762769120. Its totient is φ = 1144863181440.

The previous prime is 1550433136127. The next prime is 1550433136141. The reversal of 1550433136135 is 5316313340551.

It is not a de Polignac number, because 1550433136135 - 23 = 1550433136127 is a prime.

It is a super-2 number, since 2×15504331361352 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 301396 + ... + 1786534.

It is an arithmetic number, because the mean of its divisors is an integer number (125235173070).

Almost surely, 21550433136135 is an apocalyptic number.

1550433136135 is a deficient number, since it is larger than the sum of its proper divisors (453329632985).

1550433136135 is a wasteful number, since it uses less digits than its factorization.

1550433136135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1501218.

The product of its (nonzero) digits is 243000, while the sum is 40.

Adding to 1550433136135 its reverse (5316313340551), we get a palindrome (6866746476686).

The spelling of 1550433136135 in words is "one trillion, five hundred fifty billion, four hundred thirty-three million, one hundred thirty-six thousand, one hundred thirty-five".

Divisors: 1 5 13 65 16061 80305 208793 1043965 1485139 7425695 19306807 96534035 23852817479 119264087395 310086627227 1550433136135