Base | Representation |
---|---|
bin | 10010011111101… |
… | …00111101100011 |
3 | 101210221010121101 |
4 | 21033310331203 |
5 | 304204102120 |
6 | 23221135231 |
7 | 3562462654 |
oct | 1117647543 |
9 | 353833541 |
10 | 155144035 |
11 | 7a636012 |
12 | 43b5a517 |
13 | 261b0407 |
14 | 1686752b |
15 | d94890a |
hex | 93f4f63 |
155144035 has 4 divisors (see below), whose sum is σ = 186172848. Its totient is φ = 124115224.
The previous prime is 155143909. The next prime is 155144051. The reversal of 155144035 is 530441551.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530441551 = 211 ⋅2513941.
It is a cyclic number.
It is not a de Polignac number, because 155144035 - 213 = 155135843 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 155143994 and 155144012.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15514399 + ... + 15514408.
It is an arithmetic number, because the mean of its divisors is an integer number (46543212).
Almost surely, 2155144035 is an apocalyptic number.
155144035 is a deficient number, since it is larger than the sum of its proper divisors (31028813).
155144035 is an equidigital number, since it uses as much as digits as its factorization.
155144035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31028812.
The product of its (nonzero) digits is 6000, while the sum is 28.
The square root of 155144035 is about 12455.6828395717. The cubic root of 155144035 is about 537.3348733794.
Adding to 155144035 its reverse (530441551), we get a palindrome (685585586).
The spelling of 155144035 in words is "one hundred fifty-five million, one hundred forty-four thousand, thirty-five".
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