Base | Representation |
---|---|
bin | 1001000010001100000… |
… | …0010101100001000111 |
3 | 112211121120200110210120 |
4 | 2100203000111201013 |
5 | 10020330231111401 |
6 | 155144541353023 |
7 | 14133103124202 |
oct | 2204300254107 |
9 | 484546613716 |
10 | 155206113351 |
11 | 5a905894173 |
12 | 260b6268773 |
13 | 11836025ac3 |
14 | 7724d86939 |
15 | 4085b9b836 |
hex | 2423015847 |
155206113351 has 4 divisors (see below), whose sum is σ = 206941484472. Its totient is φ = 103470742232.
The previous prime is 155206113343. The next prime is 155206113407. The reversal of 155206113351 is 153311602551.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 153311602551 = 3 ⋅51103867517.
It is a cyclic number.
It is not a de Polignac number, because 155206113351 - 23 = 155206113343 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (155206113301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25867685556 + ... + 25867685561.
It is an arithmetic number, because the mean of its divisors is an integer number (51735371118).
Almost surely, 2155206113351 is an apocalyptic number.
155206113351 is a deficient number, since it is larger than the sum of its proper divisors (51735371121).
155206113351 is an equidigital number, since it uses as much as digits as its factorization.
155206113351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51735371120.
The product of its (nonzero) digits is 13500, while the sum is 33.
The spelling of 155206113351 in words is "one hundred fifty-five billion, two hundred six million, one hundred thirteen thousand, three hundred fifty-one".
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