Base | Representation |
---|---|
bin | 100011010010101010010011… |
… | …010110111101011110000111 |
3 | 202100120022110120010020211100 |
4 | 203102222103112331132013 |
5 | 130321011233101200201 |
6 | 1310040154420111143 |
7 | 44456561424050043 |
oct | 4322522326753607 |
9 | 670508416106740 |
10 | 155214000412551 |
11 | 455019848a3103 |
12 | 154a961a8354b3 |
13 | 687b804673c12 |
14 | 2a4857d427023 |
15 | 12e271428a886 |
hex | 8d2a935bd787 |
155214000412551 has 12 divisors (see below), whose sum is σ = 230257406017912. Its totient is φ = 100679351618736.
The previous prime is 155214000412517. The next prime is 155214000412567.
155214000412551 is a `hidden beast` number, since 1 + 5 + 5 + 21 + 40 + 0 + 0 + 41 + 2 + 551 = 666.
155214000412551 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 155214000412551 - 217 = 155214000281479 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (155214000402551) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 233054054341 + ... + 233054055006.
Almost surely, 2155214000412551 is an apocalyptic number.
155214000412551 is a deficient number, since it is larger than the sum of its proper divisors (75043405605361).
155214000412551 is a wasteful number, since it uses less digits than its factorization.
155214000412551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 466108109390 (or 466108109387 counting only the distinct ones).
The product of its (nonzero) digits is 40000, while the sum is 36.
It can be divided in two parts, 155214000 and 412551, that added together give a palindrome (155626551).
The spelling of 155214000412551 in words is "one hundred fifty-five trillion, two hundred fourteen billion, four hundred twelve thousand, five hundred fifty-one".
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