Base | Representation |
---|---|
bin | 100011010010101010010011… |
… | …010110111101011110001000 |
3 | 202100120022110120010020211101 |
4 | 203102222103112331132020 |
5 | 130321011233101200202 |
6 | 1310040154420111144 |
7 | 44456561424050044 |
oct | 4322522326753610 |
9 | 670508416106741 |
10 | 155214000412552 |
11 | 455019848a3104 |
12 | 154a961a8354b4 |
13 | 687b804673c13 |
14 | 2a4857d427024 |
15 | 12e271428a887 |
hex | 8d2a935bd788 |
155214000412552 has 32 divisors (see below), whose sum is σ = 292575223654200. Its totient is φ = 77194911539200.
The previous prime is 155214000412517. The next prime is 155214000412567. The reversal of 155214000412552 is 255214000412551.
155214000412552 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 148396397421636 + 6817602990916 = 12181806^2 + 2611054^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59393449 + ... + 61951672.
Almost surely, 2155214000412552 is an apocalyptic number.
It is an amenable number.
155214000412552 is a deficient number, since it is larger than the sum of its proper divisors (137361223241648).
155214000412552 is a wasteful number, since it uses less digits than its factorization.
155214000412552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121345977 (or 121345973 counting only the distinct ones).
The product of its (nonzero) digits is 80000, while the sum is 37.
Subtracting 155214000412552 from its reverse (255214000412551), we obtain a palindrome (99999999999999).
The spelling of 155214000412552 in words is "one hundred fifty-five trillion, two hundred fourteen billion, four hundred twelve thousand, five hundred fifty-two".
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