Base | Representation |
---|---|
bin | 10110100101101100100… |
… | …000011010101111000100 |
3 | 12111101202201010220102012 |
4 | 112211230200122233010 |
5 | 200413104212200200 |
6 | 3145041330033352 |
7 | 220102350105362 |
oct | 26455440325704 |
9 | 5441681126365 |
10 | 1552303631300 |
11 | 549367a27764 |
12 | 210a1b418858 |
13 | b34c6500276 |
14 | 551bbcd2632 |
15 | 2a5a40cba35 |
hex | 1696c81abc4 |
1552303631300 has 36 divisors (see below), whose sum is σ = 3368795633280. Its totient is φ = 620866751520.
The previous prime is 1552303631273. The next prime is 1552303631323. The reversal of 1552303631300 is 31363032551.
It is a super-3 number, since 3×15523036313003 (a number of 38 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 466661 + ... + 1822739.
It is an arithmetic number, because the mean of its divisors is an integer number (93577656480).
Almost surely, 21552303631300 is an apocalyptic number.
1552303631300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1552303631300 is an abundant number, since it is smaller than the sum of its proper divisors (1816492001980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1552303631300 is a wasteful number, since it uses less digits than its factorization.
1552303631300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1367540 (or 1367533 counting only the distinct ones).
The product of its (nonzero) digits is 24300, while the sum is 32.
Adding to 1552303631300 its reverse (31363032551), we get a palindrome (1583666663851).
The spelling of 1552303631300 in words is "one trillion, five hundred fifty-two billion, three hundred three million, six hundred thirty-one thousand, three hundred".
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