155310142403245 has 4 divisors (see below), whose sum is σ = 186372170883900. Its totient is φ = 124248113922592.

The previous prime is 155310142403209. The next prime is 155310142403249. The reversal of 155310142403245 is 542304241013551.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 48537166127044 + 106772976276201 = 6966862^2 + 10333101^2 .

It is a cyclic number.

It is not a de Polignac number, because 155310142403245 - 2¹³ = 155310142395053 is a prime.

It is a super-3 number, since 3×155310142403245³ (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 155310142403198 and 155310142403207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (155310142403249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15531014240320 + ... + 15531014240329.

It is an arithmetic number, because the mean of its divisors is an integer number (46593042720975).

Almost surely, 2^{155310142403245} is an apocalyptic number.

It is an amenable number.

155310142403245 is a deficient number, since it is larger than the sum of its proper divisors (31062028480655).

155310142403245 is an equidigital number, since it uses as much as digits as its factorization.

155310142403245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31062028480654.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 155310142403245 its reverse (542304241013551), we get a palindrome (697614383416796).

The spelling of 155310142403245 in words is "one hundred fifty-five trillion, three hundred ten billion, one hundred forty-two million, four hundred three thousand, two hundred forty-five".