155340133 has 4 divisors (see below), whose sum is σ = 167289388. Its totient is φ = 143390880.

The previous prime is 155340113. The next prime is 155340167. The reversal of 155340133 is 331043551.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 331043551 = 37 ⋅8947123.

It can be written as a sum of positive squares in 2 ways, for example, as 81414529 + 73925604 = 9023^2 + 8598^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-155340133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 155340098 and 155340107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (155340113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5974608 + ... + 5974633.

It is an arithmetic number, because the mean of its divisors is an integer number (41822347).

Almost surely, 2^155340133 is an apocalyptic number.

155340133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

155340133 is a deficient number, since it is larger than the sum of its proper divisors (11949255).

155340133 is a wasteful number, since it uses less digits than its factorization.

155340133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11949254.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 155340133 is about 12463.5521822633. The cubic root of 155340133 is about 537.5611704674.

Adding to 155340133 its reverse (331043551), we get a palindrome (486383684).

The spelling of 155340133 in words is "one hundred fifty-five million, three hundred forty thousand, one hundred thirty-three".