Base | Representation |
---|---|
bin | 10110100110110100100… |
… | …011101100110000101111 |
3 | 12111111212221202022110121 |
4 | 112212310203230300233 |
5 | 200423043141413434 |
6 | 3145401311145411 |
7 | 220144325646406 |
oct | 26466443546057 |
9 | 5444787668417 |
10 | 1553512451119 |
11 | 549928307a02 |
12 | 2110b8215267 |
13 | b3659a92075 |
14 | 5529467a63d |
15 | 2a6252aa7b4 |
hex | 169b48ecc2f |
1553512451119 has 2 divisors, whose sum is σ = 1553512451120. Its totient is φ = 1553512451118.
The previous prime is 1553512451107. The next prime is 1553512451131. The reversal of 1553512451119 is 9111542153551.
It is a balanced prime because it is at equal distance from previous prime (1553512451107) and next prime (1553512451131).
It is a cyclic number.
It is not a de Polignac number, because 1553512451119 - 213 = 1553512442927 is a prime.
It is a super-2 number, since 2×15535124511192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1553512451159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776756225559 + 776756225560.
It is an arithmetic number, because the mean of its divisors is an integer number (776756225560).
Almost surely, 21553512451119 is an apocalyptic number.
1553512451119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1553512451119 is an equidigital number, since it uses as much as digits as its factorization.
1553512451119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 135000, while the sum is 43.
The spelling of 1553512451119 in words is "one trillion, five hundred fifty-three billion, five hundred twelve million, four hundred fifty-one thousand, one hundred nineteen".
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