Base | Representation |
---|---|
bin | 1001000010111111010… |
… | …0111101100001100101 |
3 | 112212011120110210122012 |
4 | 2100233310331201211 |
5 | 10021300314012201 |
6 | 155222144244005 |
7 | 14141324462663 |
oct | 2205764754145 |
9 | 485146423565 |
10 | 155421235301 |
11 | 5aa06265502 |
12 | 26156310605 |
13 | 1186b7760b7 |
14 | 7745783c33 |
15 | 40999e15bb |
hex | 242fd3d865 |
155421235301 has 2 divisors, whose sum is σ = 155421235302. Its totient is φ = 155421235300.
The previous prime is 155421235213. The next prime is 155421235303. The reversal of 155421235301 is 103532124551.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 154724222500 + 697012801 = 393350^2 + 26401^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-155421235301 is a prime.
Together with 155421235303, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155421235303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77710617650 + 77710617651.
It is an arithmetic number, because the mean of its divisors is an integer number (77710617651).
Almost surely, 2155421235301 is an apocalyptic number.
It is an amenable number.
155421235301 is a deficient number, since it is larger than the sum of its proper divisors (1).
155421235301 is an equidigital number, since it uses as much as digits as its factorization.
155421235301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 155421235301 its reverse (103532124551), we get a palindrome (258953359852).
The spelling of 155421235301 in words is "one hundred fifty-five billion, four hundred twenty-one million, two hundred thirty-five thousand, three hundred one".
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