15550393000413 has 4 divisors (see below), whose sum is σ = 20733857333888. Its totient is φ = 10366928666940.

The previous prime is 15550393000393. The next prime is 15550393000463. The reversal of 15550393000413 is 31400039305551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 15550393000413 - 2⁸ = 15550393000157 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15550393000463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2591732166733 + ... + 2591732166738.

It is an arithmetic number, because the mean of its divisors is an integer number (5183464333472).

Almost surely, 2^{15550393000413} is an apocalyptic number.

It is an amenable number.

15550393000413 is a deficient number, since it is larger than the sum of its proper divisors (5183464333475).

15550393000413 is an equidigital number, since it uses as much as digits as its factorization.

15550393000413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5183464333474.

The product of its (nonzero) digits is 121500, while the sum is 39.

The spelling of 15550393000413 in words is "fifteen trillion, five hundred fifty billion, three hundred ninety-three million, four hundred thirteen", and thus it is an aban number.