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1555407523457 is a prime number
BaseRepresentation
bin10110101000100101100…
…000110100111010000001
312111200210000122221222222
4112220211200310322001
5200440433311222312
63150313325140425
7220242306543554
oct26504540647201
95450700587888
101555407523457
1154a70aaa7897
122115469ba715
13b389c58ba48
14553d422069b
152a6d6843672
hex16a25834e81

1555407523457 has 2 divisors, whose sum is σ = 1555407523458. Its totient is φ = 1555407523456.

The previous prime is 1555407523343. The next prime is 1555407523459. The reversal of 1555407523457 is 7543257045551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1548653313601 + 6754209856 = 1244449^2 + 82184^2 .

It is a cyclic number.

It is not a de Polignac number, because 1555407523457 - 210 = 1555407522433 is a prime.

Together with 1555407523459, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1555407523399 and 1555407523408.

It is not a weakly prime, because it can be changed into another prime (1555407523459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 777703761728 + 777703761729.

It is an arithmetic number, because the mean of its divisors is an integer number (777703761729).

Almost surely, 21555407523457 is an apocalyptic number.

It is an amenable number.

1555407523457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1555407523457 is an equidigital number, since it uses as much as digits as its factorization.

1555407523457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14700000, while the sum is 53.

The spelling of 1555407523457 in words is "one trillion, five hundred fifty-five billion, four hundred seven million, five hundred twenty-three thousand, four hundred fifty-seven".