Base | Representation |
---|---|
bin | 11101110011100000… |
… | …10010001011001011 |
3 | 1112022011100111200220 |
4 | 32321300102023023 |
5 | 230232321003303 |
6 | 11203444201123 |
7 | 1104346116165 |
oct | 167160221313 |
9 | 45264314626 |
10 | 16001344203 |
11 | 6871383809 |
12 | 31269991a3 |
13 | 1680137010 |
14 | abb201935 |
15 | 639bae053 |
hex | 3b9c122cb |
16001344203 has 8 divisors (see below), whose sum is σ = 22976289168. Its totient is φ = 9846981024.
The previous prime is 16001344193. The next prime is 16001344243. The reversal of 16001344203 is 30244310061.
16001344203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 16001344203 - 29 = 16001343691 is a prime.
It is not an unprimeable number, because it can be changed into a prime (16001344243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 205145400 + ... + 205145477.
It is an arithmetic number, because the mean of its divisors is an integer number (2872036146).
Almost surely, 216001344203 is an apocalyptic number.
16001344203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
16001344203 is a deficient number, since it is larger than the sum of its proper divisors (6974944965).
16001344203 is a wasteful number, since it uses less digits than its factorization.
16001344203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 410290893.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 16001344203 its reverse (30244310061), we get a palindrome (46245654264).
The spelling of 16001344203 in words is "sixteen billion, one million, three hundred forty-four thousand, two hundred three".
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