Base | Representation |
---|---|
bin | 1110100110111010000101… |
… | …1100001010100101010111 |
3 | 2002212110202220112201101212 |
4 | 3221232201130022211113 |
5 | 4101123114324004103 |
6 | 54054332042012035 |
7 | 3245261126616134 |
oct | 351564134124527 |
9 | 62773686481355 |
10 | 16061591234903 |
11 | 51327565888a5 |
12 | 1974a164a701b |
13 | 8c67a87cc7c6 |
14 | 3d7556c6358b |
15 | 1ccbeb19a7d8 |
hex | e9ba170a957 |
16061591234903 has 2 divisors, whose sum is σ = 16061591234904. Its totient is φ = 16061591234902.
The previous prime is 16061591234873. The next prime is 16061591234929. The reversal of 16061591234903 is 30943219516061.
It is a strong prime.
It is an emirp because it is prime and its reverse (30943219516061) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16061591234903 - 212 = 16061591230807 is a prime.
It is a super-2 number, since 2×160615912349032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16061591234963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8030795617451 + 8030795617452.
It is an arithmetic number, because the mean of its divisors is an integer number (8030795617452).
Almost surely, 216061591234903 is an apocalyptic number.
16061591234903 is a deficient number, since it is larger than the sum of its proper divisors (1).
16061591234903 is an equidigital number, since it uses as much as digits as its factorization.
16061591234903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1049760, while the sum is 50.
The spelling of 16061591234903 in words is "sixteen trillion, sixty-one billion, five hundred ninety-one million, two hundred thirty-four thousand, nine hundred three".
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