Base | Representation |
---|---|
bin | 1110101001011010011101… |
… | …1110010001110111001111 |
3 | 2010000120220012101112200121 |
4 | 3222112213132101313033 |
5 | 4102324301341002023 |
6 | 54130212004005411 |
7 | 3251344021266046 |
oct | 352264736216717 |
9 | 63016805345617 |
10 | 16104642125263 |
11 | 5149a386a5a2a |
12 | 1981230090867 |
13 | 8ca879974023 |
14 | 3d967c6c355d |
15 | 1cddba929d5d |
hex | ea5a7791dcf |
16104642125263 has 2 divisors, whose sum is σ = 16104642125264. Its totient is φ = 16104642125262.
The previous prime is 16104642125261. The next prime is 16104642125309. The reversal of 16104642125263 is 36252124640161.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16104642125263 - 21 = 16104642125261 is a prime.
Together with 16104642125261, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16104642125261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8052321062631 + 8052321062632.
It is an arithmetic number, because the mean of its divisors is an integer number (8052321062632).
Almost surely, 216104642125263 is an apocalyptic number.
16104642125263 is a deficient number, since it is larger than the sum of its proper divisors (1).
16104642125263 is an equidigital number, since it uses as much as digits as its factorization.
16104642125263 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 16104642125263 in words is "sixteen trillion, one hundred four billion, six hundred forty-two million, one hundred twenty-five thousand, two hundred sixty-three".
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