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16114350512437 is a prime number
BaseRepresentation
bin1110101001111110101000…
…1000110101100100110101
32010001111221210102201012221
43222133222020311210311
54103004142212344222
654134455212242341
73252136425232612
oct352375210654465
963044853381187
1016114350512437
11515306a844a01
12198309b4703b1
138cb76610c118
143d9d1dc17509
151ce287dd40c7
hexea7ea235935

16114350512437 has 2 divisors, whose sum is σ = 16114350512438. Its totient is φ = 16114350512436.

The previous prime is 16114350512341. The next prime is 16114350512471. The reversal of 16114350512437 is 73421505341161.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13341479454801 + 2772871057636 = 3652599^2 + 1665194^2 .

It is a cyclic number.

It is not a de Polignac number, because 16114350512437 - 211 = 16114350510389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16114350512393 and 16114350512402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16114350512497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8057175256218 + 8057175256219.

It is an arithmetic number, because the mean of its divisors is an integer number (8057175256219).

Almost surely, 216114350512437 is an apocalyptic number.

It is an amenable number.

16114350512437 is a deficient number, since it is larger than the sum of its proper divisors (1).

16114350512437 is an equidigital number, since it uses as much as digits as its factorization.

16114350512437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 43.

Adding to 16114350512437 its reverse (73421505341161), we get a palindrome (89535855853598).

The spelling of 16114350512437 in words is "sixteen trillion, one hundred fourteen billion, three hundred fifty million, five hundred twelve thousand, four hundred thirty-seven".