Base | Representation |
---|---|
bin | 1110101010000011100001… |
… | …0000100011111001110010 |
3 | 2010001122100010122111202010 |
4 | 3222200320100203321302 |
5 | 4103014333224110200 |
6 | 54135233232103350 |
7 | 3252214051450644 |
oct | 352407020437162 |
9 | 63048303574663 |
10 | 16115661160050 |
11 | 5153682654951 |
12 | 19833a6394b56 |
13 | 8cb91480465a |
14 | 3da005d0a894 |
15 | 1ce312ec9150 |
hex | ea838423e72 |
16115661160050 has 24 divisors (see below), whose sum is σ = 39966839677296. Its totient is φ = 4297509642640.
The previous prime is 16115661160033. The next prime is 16115661160087. The reversal of 16115661160050 is 5006116651161.
It is a super-2 number, since 2×161156611600502 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 16115661159990 and 16115661160008.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 53718870384 + ... + 53718870683.
It is an arithmetic number, because the mean of its divisors is an integer number (1665284986554).
Almost surely, 216115661160050 is an apocalyptic number.
16115661160050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
16115661160050 is an abundant number, since it is smaller than the sum of its proper divisors (23851178517246).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
16115661160050 is a wasteful number, since it uses less digits than its factorization.
16115661160050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107437741082 (or 107437741077 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 39.
The spelling of 16115661160050 in words is "sixteen trillion, one hundred fifteen billion, six hundred sixty-one million, one hundred sixty thousand, fifty".
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