Base | Representation |
---|---|
bin | 1110101010100100001110… |
… | …0001001110001000101111 |
3 | 2010002110222221121100201102 |
4 | 3222221003201032020233 |
5 | 4103140323120330221 |
6 | 54143244313233315 |
7 | 3252644440452332 |
oct | 352510341161057 |
9 | 63073887540642 |
10 | 16124440011311 |
11 | 5157378028825 |
12 | 198503640283b |
13 | 8cc6b35043b8 |
14 | 3da5d9bd6619 |
15 | 1ce678a7030b |
hex | eaa4384e22f |
16124440011311 has 4 divisors (see below), whose sum is σ = 16240443177000. Its totient is φ = 16008436845624.
The previous prime is 16124440011299. The next prime is 16124440011319. The reversal of 16124440011311 is 11311004442161.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16124440011311 - 218 = 16124439749167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16124440011319) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58001582636 + ... + 58001582913.
It is an arithmetic number, because the mean of its divisors is an integer number (4060110794250).
Almost surely, 216124440011311 is an apocalyptic number.
16124440011311 is a deficient number, since it is larger than the sum of its proper divisors (116003165689).
16124440011311 is a wasteful number, since it uses less digits than its factorization.
16124440011311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 116003165688.
The product of its (nonzero) digits is 2304, while the sum is 29.
Adding to 16124440011311 its reverse (11311004442161), we get a palindrome (27435444453472).
The spelling of 16124440011311 in words is "sixteen trillion, one hundred twenty-four billion, four hundred forty million, eleven thousand, three hundred eleven".
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