Base | Representation |
---|---|
bin | 1001011001001000001… |
… | …1010100111000011101 |
3 | 120102111202002102001020 |
4 | 2112102003110320131 |
5 | 10120433204313303 |
6 | 202044001234353 |
7 | 14441516343333 |
oct | 2262203247035 |
9 | 512452072036 |
10 | 161364135453 |
11 | 62485936334 |
12 | 273346329b9 |
13 | 122a7a6bc71 |
14 | 7b4ab6bb53 |
15 | 42e65eaa53 |
hex | 25920d4e1d |
161364135453 has 4 divisors (see below), whose sum is σ = 215152180608. Its totient is φ = 107576090300.
The previous prime is 161364135433. The next prime is 161364135521. The reversal of 161364135453 is 354531463161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 161364135453 - 28 = 161364135197 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (161364135403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26894022573 + ... + 26894022578.
It is an arithmetic number, because the mean of its divisors is an integer number (53788045152).
Almost surely, 2161364135453 is an apocalyptic number.
It is an amenable number.
161364135453 is a deficient number, since it is larger than the sum of its proper divisors (53788045155).
161364135453 is an equidigital number, since it uses as much as digits as its factorization.
161364135453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53788045154.
The product of its digits is 388800, while the sum is 42.
The spelling of 161364135453 in words is "one hundred sixty-one billion, three hundred sixty-four million, one hundred thirty-five thousand, four hundred fifty-three".
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