Base | Representation |
---|---|
bin | 1001011001001000111… |
… | …0110001010100000101 |
3 | 120102111221201211022211 |
4 | 2112102032301110011 |
5 | 10120434441313433 |
6 | 202044145423421 |
7 | 14441554006654 |
oct | 2262216612405 |
9 | 512457654284 |
10 | 161367135493 |
11 | 624875a5303 |
12 | 2733563ab71 |
13 | 122a857c635 |
14 | 7b4b30d19b |
15 | 42e69de8cd |
hex | 25923b1505 |
161367135493 has 2 divisors, whose sum is σ = 161367135494. Its totient is φ = 161367135492.
The previous prime is 161367135491. The next prime is 161367135509. The reversal of 161367135493 is 394531763161.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84583833889 + 76783301604 = 290833^2 + 277098^2 .
It is a cyclic number.
It is not a de Polignac number, because 161367135493 - 21 = 161367135491 is a prime.
Together with 161367135491, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (161367135491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80683567746 + 80683567747.
It is an arithmetic number, because the mean of its divisors is an integer number (80683567747).
Almost surely, 2161367135493 is an apocalyptic number.
It is an amenable number.
161367135493 is a deficient number, since it is larger than the sum of its proper divisors (1).
161367135493 is an equidigital number, since it uses as much as digits as its factorization.
161367135493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1224720, while the sum is 49.
The spelling of 161367135493 in words is "one hundred sixty-one billion, three hundred sixty-seven million, one hundred thirty-five thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •