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161402399857 is a prime number
BaseRepresentation
bin1001011001010001010…
…1010010110001110001
3120102121102002102221101
42112110111102301301
510121023003243412
6202051445324401
714442462522346
oct2262425226161
9512542072841
10161402399857
11624a54a0a06
1227345406701
13122b297881a
147b51c8c7cd
1542e9b58457
hex2594552c71

161402399857 has 2 divisors, whose sum is σ = 161402399858. Its totient is φ = 161402399856.

The previous prime is 161402399833. The next prime is 161402399929. The reversal of 161402399857 is 758993204161.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98079206976 + 63323192881 = 313176^2 + 251641^2 .

It is a cyclic number.

It is not a de Polignac number, because 161402399857 - 215 = 161402367089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 161402399798 and 161402399807.

It is not a weakly prime, because it can be changed into another prime (161402399657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80701199928 + 80701199929.

It is an arithmetic number, because the mean of its divisors is an integer number (80701199929).

It is a 1-persistent number, because it is pandigital, but 2⋅161402399857 = 322804799714 is not.

Almost surely, 2161402399857 is an apocalyptic number.

It is an amenable number.

161402399857 is a deficient number, since it is larger than the sum of its proper divisors (1).

161402399857 is an equidigital number, since it uses as much as digits as its factorization.

161402399857 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 161402399857 in words is "one hundred sixty-one billion, four hundred two million, three hundred ninety-nine thousand, eight hundred fifty-seven".