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1614113 = 10315671
BaseRepresentation
bin110001010000100100001
310001000010222
412022010201
5403122423
654332425
716501604
oct6120441
93030128
101614113
11a02786
1265a115
134468c7
1430033b
1521d3c8
hex18a121

1614113 has 4 divisors (see below), whose sum is σ = 1629888. Its totient is φ = 1598340.

The previous prime is 1614083. The next prime is 1614149. The reversal of 1614113 is 3114161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1614113 - 212 = 1610017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1614091 and 1614100.

It is not an unprimeable number, because it can be changed into a prime (1614413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7733 + ... + 7938.

It is an arithmetic number, because the mean of its divisors is an integer number (407472).

21614113 is an apocalyptic number.

It is an amenable number.

1614113 is a deficient number, since it is larger than the sum of its proper divisors (15775).

1614113 is a wasteful number, since it uses less digits than its factorization.

1614113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15774.

The product of its digits is 72, while the sum is 17.

The square root of 1614113 is about 1270.4774693004. The cubic root of 1614113 is about 117.3035922023.

Adding to 1614113 its reverse (3114161), we get a palindrome (4728274).

The spelling of 1614113 in words is "one million, six hundred fourteen thousand, one hundred thirteen".

Divisors: 1 103 15671 1614113