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16142032019 is a prime number
BaseRepresentation
bin11110000100010001…
…11101110010010011
31112122222002012002202
433002020331302103
5231024330011034
611225431433415
71111005002561
oct170210756223
945588065082
1016142032019
116933835633
123165b2586b
1316a3325449
14ad1b84a31
156471ee47e
hex3c223dc93

16142032019 has 2 divisors, whose sum is σ = 16142032020. Its totient is φ = 16142032018.

The previous prime is 16142032013. The next prime is 16142032021. The reversal of 16142032019 is 91023024161.

16142032019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16142032019 is a prime.

It is a super-2 number, since 2×161420320192 (a number of 21 digits) contains 22 as substring.

Together with 16142032021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 16142031982 and 16142032000.

It is not a weakly prime, because it can be changed into another prime (16142032013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8071016009 + 8071016010.

It is an arithmetic number, because the mean of its divisors is an integer number (8071016010).

Almost surely, 216142032019 is an apocalyptic number.

16142032019 is a deficient number, since it is larger than the sum of its proper divisors (1).

16142032019 is an equidigital number, since it uses as much as digits as its factorization.

16142032019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 16142032019 in words is "sixteen billion, one hundred forty-two million, thirty-two thousand, nineteen".