Search a number
-
+
161445014223 = 353815004741
BaseRepresentation
bin1001011001011011011…
…1110110101011001111
3120102201101021110212020
42112112313312223033
510121114410423343
6202100010541223
714443520656443
oct2262667665317
9512641243766
10161445014223
1162517557799
1227357737813
13122bb74931c
147b577c2823
1542ed774b83
hex2596df6acf

161445014223 has 4 divisors (see below), whose sum is σ = 215260018968. Its totient is φ = 107630009480.

The previous prime is 161445014219. The next prime is 161445014233. The reversal of 161445014223 is 322410544161.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 161445014223 - 22 = 161445014219 is a prime.

It is a super-3 number, since 3×1614450142233 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (161445014233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26907502368 + ... + 26907502373.

It is an arithmetic number, because the mean of its divisors is an integer number (53815004742).

Almost surely, 2161445014223 is an apocalyptic number.

161445014223 is a deficient number, since it is larger than the sum of its proper divisors (53815004745).

161445014223 is an equidigital number, since it uses as much as digits as its factorization.

161445014223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53815004744.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 161445014223 its reverse (322410544161), we get a palindrome (483855558384).

The spelling of 161445014223 in words is "one hundred sixty-one billion, four hundred forty-five million, fourteen thousand, two hundred twenty-three".

Divisors: 1 3 53815004741 161445014223