Base | Representation |
---|---|
bin | 11110000100100110… |
… | …10100000010110111 |
3 | 1112200011012000002212 |
4 | 33002103110002313 |
5 | 231031023312011 |
6 | 11230005524035 |
7 | 1111040031221 |
oct | 170223240267 |
9 | 45604160085 |
10 | 16144744631 |
11 | 6935318664 |
12 | 3166a1361b |
13 | 16a3a65042 |
14 | ad228d411 |
15 | 64758808b |
hex | 3c24d40b7 |
16144744631 has 2 divisors, whose sum is σ = 16144744632. Its totient is φ = 16144744630.
The previous prime is 16144744573. The next prime is 16144744633. The reversal of 16144744631 is 13644744161.
It is a strong prime.
It is an emirp because it is prime and its reverse (13644744161) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16144744631 is a prime.
It is a super-3 number, since 3×161447446313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 16144744633, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16144744633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8072372315 + 8072372316.
It is an arithmetic number, because the mean of its divisors is an integer number (8072372316).
Almost surely, 216144744631 is an apocalyptic number.
16144744631 is a deficient number, since it is larger than the sum of its proper divisors (1).
16144744631 is an equidigital number, since it uses as much as digits as its factorization.
16144744631 is an evil number, because the sum of its binary digits is even.
The product of its digits is 193536, while the sum is 41.
The spelling of 16144744631 in words is "sixteen billion, one hundred forty-four million, seven hundred forty-four thousand, six hundred thirty-one".
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