Base | Representation |
---|---|
bin | 11110000100101110… |
… | …11000011010111101 |
3 | 1112200020012012001221 |
4 | 33002113120122331 |
5 | 231031311424013 |
6 | 11230044433341 |
7 | 1111052062444 |
oct | 170227303275 |
9 | 45606165057 |
10 | 16145811133 |
11 | 6935986971 |
12 | 3167248851 |
13 | 16a40495ca |
14 | ad2489d5b |
15 | 6476e908d |
hex | 3c25d86bd |
16145811133 has 2 divisors, whose sum is σ = 16145811134. Its totient is φ = 16145811132.
The previous prime is 16145811131. The next prime is 16145811181. The reversal of 16145811133 is 33111854161.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8356336569 + 7789474564 = 91413^2 + 88258^2 .
It is a cyclic number.
It is not a de Polignac number, because 16145811133 - 21 = 16145811131 is a prime.
Together with 16145811131, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16145811131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8072905566 + 8072905567.
It is an arithmetic number, because the mean of its divisors is an integer number (8072905567).
Almost surely, 216145811133 is an apocalyptic number.
It is an amenable number.
16145811133 is a deficient number, since it is larger than the sum of its proper divisors (1).
16145811133 is an equidigital number, since it uses as much as digits as its factorization.
16145811133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8640, while the sum is 34.
The spelling of 16145811133 in words is "sixteen billion, one hundred forty-five million, eight hundred eleven thousand, one hundred thirty-three".
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