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16214113 is a prime number
BaseRepresentation
bin111101110110…
…100001100001
31010111202120201
4331312201201
513122322423
61335305201
7254550316
oct75664141
933452521
1016214113
1191749a3
12551b201
133489166
142220d0d
1516542ad
hexf76861

16214113 has 2 divisors, whose sum is σ = 16214114. Its totient is φ = 16214112.

The previous prime is 16214111. The next prime is 16214119. The reversal of 16214113 is 31141261.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16184529 + 29584 = 4023^2 + 172^2 .

It is an emirp because it is prime and its reverse (31141261) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16214113 - 21 = 16214111 is a prime.

Together with 16214111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (16214111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8107056 + 8107057.

It is an arithmetic number, because the mean of its divisors is an integer number (8107057).

Almost surely, 216214113 is an apocalyptic number.

It is an amenable number.

16214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

16214113 is an equidigital number, since it uses as much as digits as its factorization.

16214113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 19.

The square root of 16214113 is about 4026.6751793508. The cubic root of 16214113 is about 253.1032558266.

Adding to 16214113 its reverse (31141261), we get a palindrome (47355374).

The spelling of 16214113 in words is "sixteen million, two hundred fourteen thousand, one hundred thirteen".